Lawn Cher'
NAXJA Forum User
- Location
- Westampton, NJ
Setting your house at a cooler temperature at any given outside temperature will create a steeper temperature gradient than leaving it at a higher temperature setting. This is basic conductive heat transfer, Q=(H)(A)(T1-T2)/(X) where Q is the heat lost, H is the thermal conductivity of the material (in this case the walls of your house,) A is the surface area being considered, T1-T2 is the temperature difference (between inside and outside temps,) and X is the thickness of the material. In this case, heat is transferring from outside your house to the cooler air inside. The greater the temperature difference the more Q you lose and the more your AC system has to work. Same idea works in the opposite direction in the winter when you are heating your house. Also, having more effective insulation lowers the value for H in the equation, saving Q.